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Variable initialization will be evaluated to last valid evaluation #2

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VincentDamour opened this issue Jul 8, 2016 · 0 comments
Open

Variable initialization will be evaluated to last valid evaluation #2

VincentDamour opened this issue Jul 8, 2016 · 0 comments

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@VincentDamour
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The problem

When I initialize a variable, the output will be the last valid expression. For example:

let x = 5;
x
let y = 8;
y

The output will be:

5
5
8
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@VincentDamour