From e5b07b858dc4466aa3025d8ce21fe7e2b018cddc Mon Sep 17 00:00:00 2001
From: thinkasany <480968828@qq.com>
Date: Fri, 3 Nov 2023 01:28:27 +0800
Subject: [PATCH] feat: update sql solution to lc problem: No.0585

---
 solution/0500-0599/0585.Investments in 2016/README.md    | 6 +++---
 solution/0500-0599/0585.Investments in 2016/README_EN.md | 6 +++---
 solution/0500-0599/0585.Investments in 2016/Solution.sql | 6 +++---
 3 files changed, 9 insertions(+), 9 deletions(-)

diff --git a/solution/0500-0599/0585.Investments in 2016/README.md b/solution/0500-0599/0585.Investments in 2016/README.md
index ec13524ed04fa..fb0f5002173a1 100644
--- a/solution/0500-0599/0585.Investments in 2016/README.md	
+++ b/solution/0500-0599/0585.Investments in 2016/README.md	
@@ -84,11 +84,11 @@ WITH
     T AS (
         SELECT
             tiv_2016,
-            COUNT(pid) OVER (PARTITION BY tiv_2015) AS cnt1,
-            COUNT(pid) OVER (PARTITION BY CONCAT(lat, '-', lon)) AS cnt2
+            COUNT(1) OVER (PARTITION BY tiv_2015) AS cnt1,
+            COUNT(1) OVER (PARTITION BY lat, lon) AS cnt2
         FROM Insurance
     )
-SELECT ROUND(IFNULL(SUM(tiv_2016), 0), 2) AS tiv_2016
+SELECT ROUND(SUM(tiv_2016), 2) AS tiv_2016
 FROM T
 WHERE cnt1 > 1 AND cnt2 = 1;
 ```
diff --git a/solution/0500-0599/0585.Investments in 2016/README_EN.md b/solution/0500-0599/0585.Investments in 2016/README_EN.md
index 904c272d183c1..8df8213cc0241 100644
--- a/solution/0500-0599/0585.Investments in 2016/README_EN.md	
+++ b/solution/0500-0599/0585.Investments in 2016/README_EN.md	
@@ -77,11 +77,11 @@ WITH
     T AS (
         SELECT
             tiv_2016,
-            COUNT(pid) OVER (PARTITION BY tiv_2015) AS cnt1,
-            COUNT(pid) OVER (PARTITION BY CONCAT(lat, '-', lon)) AS cnt2
+            COUNT(1) OVER (PARTITION BY tiv_2015) AS cnt1,
+            COUNT(1) OVER (PARTITION BY lat, lon) AS cnt2
         FROM Insurance
     )
-SELECT ROUND(IFNULL(SUM(tiv_2016), 0), 2) AS tiv_2016
+SELECT ROUND(SUM(tiv_2016), 2) AS tiv_2016
 FROM T
 WHERE cnt1 > 1 AND cnt2 = 1;
 ```
diff --git a/solution/0500-0599/0585.Investments in 2016/Solution.sql b/solution/0500-0599/0585.Investments in 2016/Solution.sql
index 30b95dc8c0837..b7d9180a1244c 100644
--- a/solution/0500-0599/0585.Investments in 2016/Solution.sql	
+++ b/solution/0500-0599/0585.Investments in 2016/Solution.sql	
@@ -3,10 +3,10 @@ WITH
     T AS (
         SELECT
             tiv_2016,
-            COUNT(pid) OVER (PARTITION BY tiv_2015) AS cnt1,
-            COUNT(pid) OVER (PARTITION BY CONCAT(lat, '-', lon)) AS cnt2
+            COUNT(1) OVER (PARTITION BY tiv_2015) AS cnt1,
+            COUNT(1) OVER (PARTITION BY lat, lon) AS cnt2
         FROM Insurance
     )
-SELECT ROUND(IFNULL(SUM(tiv_2016), 0), 2) AS tiv_2016
+SELECT ROUND(SUM(tiv_2016), 2) AS tiv_2016
 FROM T
 WHERE cnt1 > 1 AND cnt2 = 1;