-
Notifications
You must be signed in to change notification settings - Fork 213
/
Copy pathContainerWithMostWater.h
37 lines (35 loc) · 1.05 KB
/
ContainerWithMostWater.h
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
/*
Author: Annie Kim, [email protected]
Date: Apr 16, 2013
Update: Aug 22, 2013
Problem: Container With Most Water
Difficulty: Easy
Source: http://leetcode.com/onlinejudge#question_11
Notes:
Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai).
n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0).
Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container.
Solution: From both sides to the center.
*/
class Solution {
public:
int maxArea(vector<int> &height) {
int res = 0;
int l = 0, r = height.size()-1;
while (l < r)
{
if (height[l] <= height[r])
{
res = max(res, (r-l) * height[l]);
l++;
}
else
{
res = max(res, (r-l) * height[r]);
r--;
}
}
return res;
}
};