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[환미니니] 8주차 문제풀이 제출 #509
[환미니니] 8주차 문제풀이 제출 #509
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Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,39 @@ | ||
// 노드 수 v, 간선 e | ||
// 시간복잡도 O(v+e) | ||
// 공간복잡도 O(v+e) | ||
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/** | ||
* // Definition for a _Node. | ||
* function _Node(val, neighbors) { | ||
* this.val = val === undefined ? 0 : val; | ||
* this.neighbors = neighbors === undefined ? [] : neighbors; | ||
* }; | ||
*/ | ||
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/** | ||
* @param {_Node} node | ||
* @return {_Node} | ||
*/ | ||
var cloneGraph = function(node) { | ||
if (!node) return | ||
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const visited = new Map() | ||
visited.set(node, new _Node(node.val)) | ||
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const que = [node] | ||
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while (que.length) { | ||
const curNode = que.shift() | ||
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for (neighbor of curNode.neighbors) { | ||
if (!visited.has(neighbor)) { | ||
visited.set(neighbor, new _Node(neighbor.val)); | ||
que.push(neighbor) | ||
} | ||
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visited.get(curNode).neighbors.push(visited.get(neighbor)) | ||
} | ||
} | ||
Comment on lines
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 👍 |
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return visited.get(node) | ||
}; |
Original file line number | Diff line number | Diff line change |
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@@ -0,0 +1,37 @@ | ||
// 시간복잡도: O(m + n) | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. clone graph 문제에서 해주신 것처럼 m, n을 무엇으로 정의했는지 적어주면 더 좋을 것 같아요. There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 좋습니다 ~ |
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// 공간복잡도: O(m + n) | ||
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/** | ||
* Definition for singly-linked list. | ||
* function ListNode(val, next) { | ||
* this.val = (val===undefined ? 0 : val) | ||
* this.next = (next===undefined ? null : next) | ||
* } | ||
*/ | ||
/** | ||
* @param {ListNode} list1 | ||
* @param {ListNode} list2 | ||
* @return {ListNode} | ||
*/ | ||
var mergeTwoLists = function(list1, list2) { | ||
let res = new ListNode() | ||
let resCopy = res | ||
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while (list1 && list2) { | ||
if (list1.val < list2.val) { | ||
res.next = new ListNode(list1.val); | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 지금은 순회를 할때마다 새로운 노드를 만들어서 할당하고 있어요. There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. 아 기존 리스트 노드를 재활용하면 되겠네요..! |
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list1 = list1.next; | ||
} else { | ||
res.next = new ListNode(list2.val); | ||
list2 = list2.next; | ||
} | ||
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res = res.next | ||
} | ||
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if (list1) res.next = list1; | ||
if (list2) res.next = list2 | ||
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return resCopy.next | ||
}; | ||
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q
나queue
로 표현해준다면 더 가독성이 높아질 것 같아요!There was a problem hiding this comment.
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변수명 좀 더 신경써서 지어야겠어요👍