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[yoonthecoder] Week 5 #870

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Jan 12, 2025
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27 changes: 27 additions & 0 deletions 3sum/yoonthecoder.js
Original file line number Diff line number Diff line change
@@ -0,0 +1,27 @@
var threeSum = function (nums) {
nums.sort((a, b) => a - b);
const results = [];
for (let i = 0; i < nums.length - 2; i++) {
if (i > 0 && nums[i] === nums[i - 1]) continue;
let left = i + 1;
let right = nums.length - 1;
while (left < right) {
const currSum = nums[i] + nums[left] + nums[right];

if (currSum == 0) {
results.push([nums[i], nums[left], nums[right]]);
left++;
right--;
// to avoid duplicates
while (left < right && nums[left] === nums[left - 1]) left++;
while (left < right && nums[right] === nums[right + 1]) right--;
} else if (currSum < 0) {
left++;
} else right--;
}
}
return results;
};

// Time complexity: O(n^2);
// Space complexity: O(n)
13 changes: 13 additions & 0 deletions best-time-to-buy-and-sell-stock/yoonthecoder.js
Original file line number Diff line number Diff line change
@@ -0,0 +1,13 @@
var maxProfit = function (prices) {
// set the initial value to Infinity so that it can always return minimum value
let minPrice = Infinity;
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minPrice를 Infinity로 지정하신건
for문의 시작값을 0으로 하여 첫 번째 가격도 최소 값이 될수 있도록 하신걸까요?
저는 인덱스를 1부터 시작했는데 이런 방법도 있었군요~!👍

let maxPrice = 0;
for (i = 0; i < prices.length; i++) {
minPrice = Math.min(prices[i], minPrice);
maxPrice = Math.max(maxPrice, prices[i + 1] - minPrice);
}
return maxPrice;
};

// Time complexity: O(n) - Iterating through the array
// Space complexity: O(1)
14 changes: 14 additions & 0 deletions group-anagrams/yoonthecoder.js
Original file line number Diff line number Diff line change
@@ -0,0 +1,14 @@
var groupAnagrams = function (strs) {
const map = new Map();

for (const str of strs) {
// split the string into each character (returns an array) => sort it => convert it to string
const sortedStr = str.split('').sort().join('');
// use the sorted Str as unique keys in the map
if (map.has(sortedStr)) {
map.get(sortedStr).push(str);
} else map.set(sortedStr, [str]);
}
// convert values into an array
return [...map.values()];
};
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