feat: update sql solution to lc problem: No.0585 (#1917)

doocs · Nov 2, 2023 · 8564bbe · 8564bbe
1 parent 8a12635
commit 8564bbe
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Showing 3 changed files with 9 additions and 9 deletions.
diff --git a/solution/0500-0599/0585.Investments in 2016/README.md b/solution/0500-0599/0585.Investments in 2016/README.md
@@ -84,11 +84,11 @@ WITH
     T AS (
         SELECT
             tiv_2016,
-            COUNT(pid) OVER (PARTITION BY tiv_2015) AS cnt1,
-            COUNT(pid) OVER (PARTITION BY CONCAT(lat, '-', lon)) AS cnt2
+            COUNT(1) OVER (PARTITION BY tiv_2015) AS cnt1,
+            COUNT(1) OVER (PARTITION BY lat, lon) AS cnt2
         FROM Insurance
     )
-SELECT ROUND(IFNULL(SUM(tiv_2016), 0), 2) AS tiv_2016
+SELECT ROUND(SUM(tiv_2016), 2) AS tiv_2016
 FROM T
 WHERE cnt1 > 1 AND cnt2 = 1;
 ```

diff --git a/solution/0500-0599/0585.Investments in 2016/README_EN.md b/solution/0500-0599/0585.Investments in 2016/README_EN.md
@@ -77,11 +77,11 @@ WITH
     T AS (
         SELECT
             tiv_2016,
-            COUNT(pid) OVER (PARTITION BY tiv_2015) AS cnt1,
-            COUNT(pid) OVER (PARTITION BY CONCAT(lat, '-', lon)) AS cnt2
+            COUNT(1) OVER (PARTITION BY tiv_2015) AS cnt1,
+            COUNT(1) OVER (PARTITION BY lat, lon) AS cnt2
         FROM Insurance
     )
-SELECT ROUND(IFNULL(SUM(tiv_2016), 0), 2) AS tiv_2016
+SELECT ROUND(SUM(tiv_2016), 2) AS tiv_2016
 FROM T
 WHERE cnt1 > 1 AND cnt2 = 1;
 ```

diff --git a/solution/0500-0599/0585.Investments in 2016/Solution.sql b/solution/0500-0599/0585.Investments in 2016/Solution.sql
@@ -3,10 +3,10 @@ WITH
     T AS (
         SELECT
             tiv_2016,
-            COUNT(pid) OVER (PARTITION BY tiv_2015) AS cnt1,
-            COUNT(pid) OVER (PARTITION BY CONCAT(lat, '-', lon)) AS cnt2
+            COUNT(1) OVER (PARTITION BY tiv_2015) AS cnt1,
+            COUNT(1) OVER (PARTITION BY lat, lon) AS cnt2
         FROM Insurance
     )
-SELECT ROUND(IFNULL(SUM(tiv_2016), 0), 2) AS tiv_2016
+SELECT ROUND(SUM(tiv_2016), 2) AS tiv_2016
 FROM T
 WHERE cnt1 > 1 AND cnt2 = 1;