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DisplayPort AUX Channel Pin Mapping
Tim Ansell edited this page May 10, 2016
·
1 revision
The AUX channels are kind of peculiar. There are two sets of differential pairs driving the same line because of the bi-directional nature.
You need to do something like this;
NET "RX_AUXI_P" LOC = "R11" |IOSTANDARD = LVDS_33 | DIFF_TERM = "TRUE";
NET "RX_AUXI_N" LOC = "T11" |IOSTANDARD = LVDS_33 | DIFF_TERM = "TRUE";
NET "RX_AUXO_P" LOC = "T10" |IOSTANDARD = LVDS_33;
NET "RX_AUXO_N" LOC = "U10" |IOSTANDARD = LVDS_33;
NET "TX_AUXI_P" LOC = "T15" |IOSTANDARD = LVDS_33 | DIFF_TERM = "TRUE";
NET "TX_AUXI_N" LOC = "U15" |IOSTANDARD = LVDS_33 | DIFF_TERM = "TRUE";
NET "TX_AUXO_P" LOC = "U16" |IOSTANDARD = LVDS_33;
NET "TX_AUXO_N" LOC = "V15" |IOSTANDARD = LVDS_33;
and
input RX_AUXI_P,
input RX_AUXI_N,
output RX_AUXO_P,
output RX_AUXO_P,
input TX_AUXI_P,
input TX_AUXI_N,
output TX_AUXO_P,
output TX_AUXO_P
);
wire tx_aux_r;
wire tx_aux_w;
wire tx_aux_oe;
OBUFTDS tx_auxi_ibufds (
.O(tx_aux_r),
.I(TX_AUXI_P),
.IB(TX_AUXI_N)
);
OBUFTDS tx_auxo_obufds (
.I(tx_aux_w),
.O(TX_AUXO_P),
.OB(TX_AUXO_N),
.T(tx_aux_oe)
);
wire rx_aux_r;
wire rx_aux_w;
wire rx_aux_oe;
OBUFTDS rx_auxi_ibufds (
.O(rx_aux_r),
.I(RX_AUXI_P),
.IB(RX_AUXI_N)
);
OBUFTDS rx_auxo_obufds (
.I(rx_aux_w),
.O(RX_AUXO_P),
.OB(RX_AUXO_N),
.T(rx_aux_oe)
);